Remove matched patterns in a string

Alias for str_replace(string, pattern, "").

str_remove(string, pattern)

str_remove_all(string, pattern)

Arguments

string

string	Input vector. Either a character vector, or something coercible to one.
pattern	Pattern to look for. The default interpretation is a regular expression, as described in stringi::stringi-search-regex. Control options with `regex()`. Match a fixed string (i.e. by comparing only bytes), using `fixed()`. This is fast, but approximate. Generally, for matching human text, you'll want `coll()` which respects character matching rules for the specified locale. Match character, word, line and sentence boundaries with `boundary()`. An empty pattern, "", is equivalent to `boundary("character")`.

Input vector. Either a character vector, or something coercible to one.

pattern

Pattern to look for.

The default interpretation is a regular expression, as described in stringi::stringi-search-regex. Control options with regex().

Match a fixed string (i.e. by comparing only bytes), using fixed(). This is fast, but approximate. Generally, for matching human text, you'll want coll() which respects character matching rules for the specified locale.

Match character, word, line and sentence boundaries with boundary(). An empty pattern, "", is equivalent to boundary("character").

Value

A character vector.

Examples

fruits <- c("one apple", "two pears", "three bananas")
str_remove(fruits, "[aeiou]")
#> [1] "ne apple"     "tw pears"     "thre bananas"
str_remove_all(fruits, "[aeiou]")
#> [1] "n ppl"    "tw prs"   "thr bnns"

Arguments

Value

See also

Examples

Contents