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Remove matched patterns in a string

Source: R/remove.r
str_remove.Rd

Alias for str_replace(string, pattern, "").

Usage

str_remove(string, pattern)

str_remove_all(string, pattern)

Arguments

string

Input vector. Either a character vector, or something coercible to one.

pattern

Pattern to look for.

The default interpretation is a regular expression, as described vignette("regular-expressions").Control options with regex().

Match a fixed string (i.e. by comparing only bytes), using fixed(). This is fast, but approximate. Generally, for matching human text, you'll want coll() which respects character matching rules for the specified locale.

Match character, word, line and sentence boundaries with boundary(). An empty pattern, "", is equivalent to boundary("character").

Value

A character vector.

See also

str_replace() for the underlying implementation.

Examples

fruits <- c("one apple", "two pears", "three bananas")
str_remove(fruits, "[aeiou]")
#> [1] "ne apple"     "tw pears"     "thre bananas"
str_remove_all(fruits, "[aeiou]")
#> [1] "n ppl"    "tw prs"   "thr bnns"